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3.5x^2-56x-126=0
a = 3.5; b = -56; c = -126;
Δ = b2-4ac
Δ = -562-4·3.5·(-126)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-70}{2*3.5}=\frac{-14}{7} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+70}{2*3.5}=\frac{126}{7} =18 $
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